1) Given that a^20 congruent 1 (mod 25) for all integers a such that gcd(a, 25) = 1. Find the last 2 digits. of 287^449 2) Solve the congruence equation x^10 + 11x^8 + 44x^6 + 25x^2 + 12x congruent 3 (mod 55)
