Compute the sum
21⋅2⋅3+22⋅3⋅4+23⋅4⋅5+⋯
∞∑n=0n!(n+1+δ)!=1δ⋅δ!2∞∑n=0n!(n+3)!=22⋅2!=12
answer see: https://web2.0calc.com/questions/algebra_47009#r4