An ordered pair of digits (a,b) is such that 4a5, b72 is a multiple of 66. Find a + b .
For it to be divisable by 66, it has to be divisable by 2, 3, 11.
2 just means the end is even.
18 + a + b = divisable by 3.
16 = a + b + 2
Solve for a and b. :))
=^._.^=
