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An ordered pair of digits (a,b) is such that 4a5, b72 is a multiple of 66. Find a + b .

 May 25, 2021
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For it to be divisable by 66, it has to be divisable by 2, 3, 11. 

2 just means the end is even.  

18 + a + b = divisable by 3. 

16 = a + b + 2

 

Solve for a and b. :))

=^._.^=

 May 25, 2021

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