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\(\large{\begin{array}{ccccccc} && & A & B& C & D&E\\ \times && & & & & &4\\ \hline & & & E & D& C & B&A\\ \hline \end{array}}\)

\

Solve the cryptogram above, where A,B,C,D and E are not necessarily distinct digits. Submit your answer as the 5-digit integer ABCDE.

 Jul 12, 2020
 #1
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Your 5-digit cryptogram =21,978

 

21, 978 x 4 =87,912 - which are same 5 digits in reverse.

 Jul 12, 2020

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