Find the smallest two-digit number where the product of its two digits is equal to half the number.
36 is the smallest such number:
3 x 6 =18
36 / 2 =18
(a (10) + b ) / 2 = ab
10a + b = 2ab
10a = 2ab - b
10a = b ( 2a - 1)
b = 10a / ( 2a -1)
b will be the smallest possible integer, 6, when a = 3
So....the number = 36.....just as the Guest found !!!