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A, B, C, and D are positive digits such that ABCD + BCD + CD + D + 377 = 2012. Find A + B + C + D

 Apr 6, 2021
 #1
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Are you sure you posted the correct numbers?

ABCD + BCD + CD + D + 377 = 2012.

  I fail to see how  4D + 7    can result in a '2' in the units digit ...

 Apr 6, 2021
edited by Guest  Apr 6, 2021
 #2
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Yes, because for 4D+7 to have a 2 in the units digit, it must end in 5, but 4D is even and cannot end in five. I think he posted the wrong numbers.

RiemannIntegralzzz  Apr 6, 2021

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