A, B, C, and D are positive digits such that ABCD + BCD + CD + D + 377 = 2012. Find A + B + C + D
Are you sure you posted the correct numbers?
ABCD + BCD + CD + D + 377 = 2012.
I fail to see how 4D + 7 can result in a '2' in the units digit ...
Yes, because for 4D+7 to have a 2 in the units digit, it must end in 5, but 4D is even and cannot end in five. I think he posted the wrong numbers.