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The points $(-3,2)$ and $(-2,3)$ lie on a circle whose center is on the $x$-axis. What is the radius of the circle?

 Jun 24, 2020
 #1
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The center will be      x, 0     because it is on the x axis

    the distance from the center to EACH of the points is the radius

  Then using the ditance formula:

 

(x - - 3)^2   +  (0-2)^2    =   (x- -2)^2 + (0-3)^2 

x^2 +6x+9 +4  = x^2 +4x+4 + 9

2x = 0

x= 0     and y = 0

 

(0- -3)^2 + (0-2)^2 = d^2

    9 + 4

       13 = d^2     d = sqrt 13 = r

 Jun 24, 2020

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