Oscar and Felix leave the same house driving separately to the same conference, along the same route, at a speed of x mi/h. If Oscar had driven 10 mi/h faster, he would have driven for 18 fewer minutes. If Felix had driven 20 mi/h faster, he would have driven for 30 fewer minutes. What is the distance from the house to the conference?

Guest Nov 26, 2022

#2**0 **

Let the distance ==D

Let Oscar's speed ==S

Let the usual time of arrival==T

D / [S + 10] ==T - 18 / 60,

D / [S + 20] ==T - 1/2,

D / S ==T, solve for D, S, T

**S ==40 MPH - their initial speed T ==3/2 ==1.5 hours - the usual time of arrival D ==60 miles - distance between their house and the conference venue.**

Guest Nov 26, 2022