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Oscar and Felix leave the same house driving separately to the same conference, along the same route, at a speed of x mi/h. If Oscar had driven 10 mi/h faster, he would have driven for 18 fewer minutes. If Felix had driven 20 mi/h faster, he would have driven for 30 fewer minutes. What is the distance from the house to the conference?
 Nov 26, 2022
 #1
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The distance to the conference is 35 miles.

 Nov 26, 2022
 #2
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Let the distance ==D
Let Oscar's speed ==S
Let the usual time of arrival==T


D / [S + 10] ==T - 18 / 60,    
D / [S + 20] ==T - 1/2,  
D / S ==T, solve for D, S, T


S ==40 MPH - their initial speed
T ==3/2 ==1.5 hours - the usual time of arrival
D ==60 miles - distance between their house and the conference venue.

 Nov 26, 2022

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