A man walks due west 800 feet, then due north 900 feet, then due east 1500 feet, and finally due south 100 feet. How far is he from his starting point?
+113 It helps to draw this, using some drawing app.. GeoGebra online is fine for this sort of thing.
We can calculate the length EA by EA = \(\sqrt{EF^2 + FA^2} = \sqrt{700^2 + 800^2} = \sqrt{490,000 + 640,000} = \sqrt{1,390,000} = 1,063.015\)
Now we round this off to whole feet. He is 1,063 feet from where he started.
+128475 Welcome aboard, Tuffla!!
Here's one more way
Let him start at (0,0)
When he walks 800 feet west he is at (-800, 0)
When he then walks 900 ft due north he is at (-800 , 900)
When he then walks 1500 ft due east he is at ( -800 + 1500, 900) = (700,900)
When he walks due south 100 ft he is at ( 700 , 900 - 100) = (700, 800)
And his distance from the starting point (as Tuffla calculated) is
sqrt [ 700^2 + 800^2 ] =
sqrt [ 100^2 ( 7^2 + 8^2) ] =
100 sqrt [ 113 ] ft ≈ 1063 ft
