How many ways are there to put 4 balls in 3 boxes if the balls are distinguishable but the boxes are not?
I know we have
4:0:0 | 1 way
3:1:0 | 4 ways
2:2:0 | 3 ways (???)
2:1:1 | 6 ways (???)
some things I'm not sure though...
I got it right
you can still solve if you want though :p