+4 Why:
(1*1-1)*(-1) is equal to 2 and 0?
I mean, when I solve the "parentheses" first, the product is:
(1*1-1)*(-1) = (1-1)*(-1) = (0)*(-1) = 0
But, if use the distributive property the product change to this:
(1*1-1)*(-1) = (-1)*(-1)+1 = 2
What is wrong?! Where is the problem? (or a solution xD)
If I solve like this, the multiplication in the parentheses first then the distributive property, the product seems equal to 0:
(1*1-1)*(-1) = (1-1)*(-1) = (-1)+1 = 0
So.... Does the distributive property only works with addition and subtraction??
If yes....
How do I find this product? :
(a*b*c)*3
I mean.. There's a "distributive property" for multiplication?
Thanks!
(sorry for the english.. i'm not fluent >.<)
+118658 Hi MrDavi275,
So.... Does the distributive property only works with addition and subtraction??
YES IT IS ONLY FOR ADDITION AND SUBTRACTION!!
yours (incorrect)
(1*1-1)*(-1) = (-1)*(-1)+1 = 2
mine
(1*1-1)*(-1) =(1-1)*(-1)
NOW you can use the distributive property
(1-1)*(-1)
=1*(-1) -1*(-1)
= -1--1
=-1+1
=0
+23251 Your "parentheses" first solution is correct.
However, there is a mistake in the your solution using the distributive property.
(1*1 - 1) * (-1)
Multiply the -1 times the first term 1*1
keep the subtraction sign where it is
and multiply the -1 times the second term 1.
This becomes: (1 * 1 * -1) - (1 * -1)
which is ( -1 ) - (-1 )
which is -1 + 1 = 0.
When you multiply a*b*c by 3, just use the 3 only once: answer: 3*a*b*c.
In your problem, when you multiplied 1*1 * -1, you used the -1 twice; don't do that; use it only once; therefore 1*1*-1 = -1*1*1 = -1.
+118658 Hi MrDavi275,
So.... Does the distributive property only works with addition and subtraction??
YES IT IS ONLY FOR ADDITION AND SUBTRACTION!!
yours (incorrect)
(1*1-1)*(-1) = (-1)*(-1)+1 = 2
mine
(1*1-1)*(-1) =(1-1)*(-1)
NOW you can use the distributive property
(1-1)*(-1)
=1*(-1) -1*(-1)
= -1--1
=-1+1
=0
