divide

is it 2 - (3i/-1) +5i or (2-3i/-1+5i)?

the second one 

Hi guest!

So to start, you have to multiply the denominator by the conjugate.

\(\frac{2-3i}{-1+5i}\cdot\frac{-1-5i}{-1-5i}\)= \(\frac{-17-7i}{26}\)

The answer is \(\frac{-17-7i}{26}\)

I hope this helped you, guest!

Let me know if you have any questions!

:)

it helped thank you!!