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Divide.

2−3i/−1+5i

 

in standard form for complex numbers = 

 Apr 25, 2020
 #1
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0

is it 2 - (3i/-1) +5i or (2-3i/-1+5i)?

 Apr 25, 2020
 #2
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the second one 

 Apr 25, 2020
 #3
avatar+463 
+2

Hi guest!

 

So to start, you have to multiply the denominator by the conjugate.

 

\(\frac{2-3i}{-1+5i}\cdot\frac{-1-5i}{-1-5i}\)\(\frac{-17-7i}{26}\)

 

The answer is \(\frac{-17-7i}{26}\)

 

I hope this helped you, guest!

Let me know if you have any questions!

:)

.
 Apr 25, 2020
edited by lokiisnotdead  Apr 25, 2020
 #4
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it helped thank you!!

 Apr 25, 2020
 #5
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I'm glad it did :)

lokiisnotdead  Apr 26, 2020

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