Divide.
12(cos(7π/6)+i sin(7π/6))
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4√6(cos(3π/4)+i sin(3π/4))
Enter the all values as exact values in simplest form.
____(cos(_____)+i sin(______))
+23246 If you have a problem such as a·cos(A) / b·cis(B)
you can solve it as: (a/b)·cis(A - B)
For this problem a = 12 and b = 4·sqrt(6) so a/b = sqrt(6)/2
and A = 7pi/6 and B = 3pi/4 so A - B = 5pi/12
Therefore, the answer is: sqrt(6)/2·( cos(5pi/12) + i·sin(5pi/12) )
