((log2(n^4)+5*n)/(n*log2(n))) I know I can get rid of n which is with 5 and bottom alone n, but dunno if there something else to do, when both log have same base but n is different. Thank You :)
+118658
((log2(n^4)+5*n)/(n*log2(n)))
\(n\ne0\)
\(\frac{log_2(n^4)+5n}{nlog_2(n)}\\ =\frac{4log_2(n)+5n}{nlog_2(n)}\\ =\frac{4}{n}+\frac{5}{log_2(n)}\\\)
Are you sure the brackets were in the right spots?
Started log2(n4)+5n=(n*log2(n)) so I hope they are right
How didi you het rid of that upper log2(n)? and how seperate that 4/n when n is * and 4 is + with the rest
+118658 There is no equal sign in your original question - it was a divide!
log2(n4)+5n=(n*log2(n))
\(log_2(n^4)+5n=(n*log_2(n))\\ log_2(n^4)+5n=log_2(n^n)\\ 5n=log_2(n^n)-log_2(n^4)\\ 5n=log_2(\frac{n^n}{ n^4 })\\ 5n=log_2(n^{n-4})\\ 2^{5n}=2^{log_2(n^{n-4})}\\ 2^{5n}=n^{n-4}\\ 32^n=n^{n-4}\\\)
Again, I suggest you have written the question down wrongly!
