(1! + 2! + 3! + 4! + ... + 100!) / 36 ; What is the remainder of this division?
I found 9 via the calculator, but how can i solve this problem without being too harsh on it... :( I can't believe i just tried to calculate it on the calculator but if there's a formula or something it will really help me. :)
Thanks!
(1! + 2! + 3! + 4! + ... + 100!) / 36 ; What is the remainder of this division?
I found 9 via the calculator, but how can i solve this problem without being too harsh on it... :( I can't believe i just tried to calculate it on the calculator but if there's a formula or something it will really help me. :)
Mmm, 36=1*2*3* 6
so from 6! up to 100! there will be no remainders so I am only going to look at
(1!+2!+3!+4!+5!)/36 = (1+2+6+24+120 )/36 = 153/36 = (144+9)/36
The remainder will be 9.
Can you understand my logic?