Find the sum of the positive square free divisors of 54000.
Note: A natural number is square free if it is not the multiple of any perfect square greater than 1.
Are you sure that you want the "sum" or the "number" of "free divisors of 54,000"?
54,000=(1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 25, 27, 30, 36, 40, 45, 48, 50, 54, 60, 72, 75, 80, 90, 100, 108, 120, 125, 135, 144, 150, 180, 200, 216, 225, 240, 250, 270, 300, 360, 375, 400, 432, 450, 500, 540, 600, 675, 720, 750, 900, 1000, 1080, 1125, 1200, 1350, 1500, 1800, 2000, 2160, 2250, 2700, 3000, 3375, 3600, 4500, 5400, 6000, 6750, 9000, 10800, 13500, 18000, 27000, 54000)>>Total = 80 divisors.
(1, 4, 9, 16, 25, 36, 100, 144, 225, 400, 900, 3600) >Total = 12 - these are perfect squares included in the above 80 divisors.
You simply remove these 11 perfect squares from the 80 divisors and sum up what is left.
