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Find the number of positive integers that are divisors of at least one of 10^10,18^7,18^11.

 May 29, 2022
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10^10= 2^10 * 5^10 ==[10 +1] x [10 + 1] ==121 divisors

 

18^7= 2^7 * 3^14==[7 +1] x [14 +1] ==120 divisors

 

18^11= 2^11 * 3^22==[11 + 1] x [22 +1]==276 divisors.

 May 29, 2022

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