Find the number of positive integers that are divisors of at least one of 10^10,18^7,18^11.
10^10= 2^10 * 5^10 ==[10 +1] x [10 + 1] ==121 divisors
18^7= 2^7 * 3^14==[7 +1] x [14 +1] ==120 divisors
18^11= 2^11 * 3^22==[11 + 1] x [22 +1]==276 divisors.
