We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
198
1
avatar+14 

-deleted-

 Dec 10, 2018
edited by shann0n  Dec 10, 2018
edited by shann0n  Dec 14, 2018
 #1
avatar+5225 
+3

\(\text{If there are 8 T's there are 8 C's, so we are left with 14 slots}\\ \text{This means that A=G=7}\\ P[\text{8 T's}] = \dbinom{30}{8}\dbinom{22}{8}\dbinom{14}{7}(0.29)^7(0.23)^8(0.27)^7(0.21)^8\)

 

Now the problem might actually mean there are at least 8 T's.  In which case we'd modify above to be

 

\(\large \sum \limits_{t=8}^{15}~\dbinom{30}{t}\dbinom{30-t}{t}\dbinom{30-2t}{15-t}(0.29)^{15-t}(0.23)^t(0.27)^{15-t}(0.21)^t\)

.
 Dec 10, 2018

17 Online Users

avatar