do we always need improper fraction to subtract?

Question

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483

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Guest Feb 28, 2015

+118723

+5

Best Answer

example

$$\\6\frac{3}{8}-2\frac{2}{8}\\\\
=6+\frac{3}{8}-2-\frac{2}{8}\\\\
=6-2+\frac{3}{8}-\frac{2}{8}\\\\
=4+\frac{1}{8}\\\\
=4\frac{1}{8}$$

Melody Feb 28, 2015

Melody · Answer 1 · 2015-02-28T11:33:38

example

$$\\6\frac{3}{8}-2\frac{2}{8}\\\\
=6+\frac{3}{8}-2-\frac{2}{8}\\\\
=6-2+\frac{3}{8}-\frac{2}{8}\\\\
=4+\frac{1}{8}\\\\
=4\frac{1}{8}$$

Melody · Answer 2 · 2015-02-28T07:22:04

NO Definitely not!