What is the probability that at least two of the faces match when you roll three fair six-sided dice? Express your answer as a common fraction.
first die: any number
second die: prob 5/6 that it is different from first
third die: prob 4/6 that it is different from first two
So, the probability they are all different=6/6 x 5/6 x 4/6 =120/216
So, the probability that at least 2 of them show the same face is:
1 - 120/216 = 96 / 216 =44.44%
