The faces of two dodecahedra are labeled with the numbers 1 to 12 in order to make dice. If these dice are rolled, what is the probability that the sum of the two top numbers is greater than 12?
There will be 12 x 12 = 144 possible outcomes
Outcome Frequency
2 1
3 2
4 3
5 4
6 5
7 6
8 7
9 8
10 9
11 10
12 11
____
66
So....... the probaility of a number > 12 =
[ 144 - 66 ] / 144 =
78 / 144 =
39 / 72 =
13 / 24
+113 
