+0

Does 1+1=0 ?

0
649
7
+869

$$\\\mathbf{i}=\sqrt{-1}\\ \sqrt{ab}=\sqrt{a}\times \sqrt{b} \\\textup{So:}\\ 1+1=1+\sqrt{1}\\ =1+\sqrt{(-1)\times(-1)}\\ =1+\sqrt{-1}\times \sqrt{-1}\\ =1+\mathbf{i}\times \mathbf{i}\\ =1\times \mathbf{i}^2\\ =1+(-1)=1-1=0$$

Is there a miscalculation ? Or is 1+1 really equal to 0 ?

May 2, 2015