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For what values of $y$ does the following equation have no solutions for $x$?

 

$$xy + 5y + 4x + 20=1.$$

 Nov 16, 2020
 #1
avatar+112016 
+1

1) You have to leave all the terms with an x it it on the left side and take all the other terms to the other side. 

 

2) You have to factorize the left side.

 

3) You have to to get x by it self on the left

 

4) you cannot divide by 0

 

Do as much of that as you can and then show us what you have done.

 

 

No one else answer over me. Thank you.

 Nov 16, 2020
edited by Melody  Nov 16, 2020
 #3
avatar+153 
+1

If we look at xy + 5y, we see that both terms share a factor of y . This gives me y(x + 5) + 4x + 20 = 1
Similarly,4x and 20 do share a factor of 4 , giving me y(x + 5) + 4x(x + 5) = 1

  these two terms have a factor of x + 5 , so  (y + 4)(x + 5) = 1

Dividing both sides by y + 4 and subtract both sides by to get x = 1/y + 4 - 5   am I right?

Thanks4helping  Nov 16, 2020
 #2
avatar+153 
+1

Thank you I am working on it.

 Nov 16, 2020
 #4
avatar+153 
+1

Im wrong

Thanks4helping  Nov 16, 2020
edited by Thanks4helping  Nov 17, 2020
 #5
avatar+112016 
+1

I'll take a look

 

\(xy + 5y + 4x + 20=1. \)

If we look at xy + 5y, we see that both terms share a factor of y . This gives me y(x + 5) + 4x + 20 = 1      correct


Similarly,4x and 20 do share a factor of 4 , giving me y(x + 5) + 4x(x + 5) = 1                                           

 No          4x(x+1)=4x^2+4x     and there are no squared terms in this problems.

 

y(x + 5) + 4x + 20 = 1

You need to get the 4x and the 20 onto the other side.  How do you do that?

 

After you do that you will be up to my number 3). 

 

3) You have to to get x by it self on the left

 

4) you cannot divide by 0

 

Do as much of that as you can and then show us what you have done.

 Nov 16, 2020
 #6
avatar+153 
0

Tricky tricky

Thanks4helping  Nov 17, 2020
 #7
avatar+153 
+1

x ( y + 4)  + 5 ( y + 4)  =  1 (x + 5) (y + 4)  = 1   and divide both sides by (y + 4) right

Thanks4helping  Nov 17, 2020
 #8
avatar+112016 
+2

No that is not right.  But I am glad to see that you are trying to answer me.

 

Mz instructions

y(x + 5) + 4x + 20 = 1

You need to get the 4x and the 20 onto the other side.  How do you do that?

 

I should not really work it as putting them on the other side. (Although it is common working and that is what happens)

But what I am really asking you to do is get 4x and 20  OFF the left side.

 

at the moment you have  +4x so you will have to take 4x away.    +4x-4x = 0

you also have +20 so you will need to take that away too   20-20 = 0

So the left side will be   

y(x + 5) + 4x + 20 - 4x - 20

BUT equations must stay BALANCED.

 

If you do something to one side you must do it to the other side as well.  Otherwise the scale will tip sideways.

so this is what you have to do.

y(x + 5) + 4x + 20 = 1

y(x + 5) + 4x + 20-4x-20 = 1-4x-20

 

Now simplify both sides and then get back to me with your answer.   Leave the y(x+5) alone for the moment.

 

----------------------------------------

 

After you do this tell me what is the invisible symbol between y and (x+5)  

And

what is the opposite operation to that.  Like the opposite of + is -  because  +4-4 = 0

Melody  Nov 17, 2020
 #9
avatar+153 
0

I have to get the answer melody

Thanks4helping  Nov 18, 2020
 #10
avatar+112016 
+1

I am not here to give answers.

I am here to teach.

If it is too hard for you then your teacher and your parents need to know that.

Melody  Nov 19, 2020
 #11
avatar+153 
0

 

frown

Thanks4helping  Nov 19, 2020

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