does the side lengths 8,15,17 make a right triangle
a = 8 b = 15 c = 17
$$\\ \small{\text{
$
a^2 \stackrel?= c^2-b^2 =(c-b)(c+b)
$
}}$\\$
\small{\text{
$
a^2 \stackrel?= (c-b)(c+b)
$
}}$\\$
\small{\text{
$
8*8 \stackrel?= (17-15)(17+15)
$
}}$\\$
\small{\text{
$
64 \stackrel?= (2)*(32)
$
}}$\\$
\small{\text{
$
64 = 64
$
}}$$
Yes, it is a right triangle
![]()
does the side lengths 8,15,17 make a right triangle
a = 8 b = 15 c = 17
$$\\ \small{\text{
$
a^2 \stackrel?= c^2-b^2 =(c-b)(c+b)
$
}}$\\$
\small{\text{
$
a^2 \stackrel?= (c-b)(c+b)
$
}}$\\$
\small{\text{
$
8*8 \stackrel?= (17-15)(17+15)
$
}}$\\$
\small{\text{
$
64 \stackrel?= (2)*(32)
$
}}$\\$
\small{\text{
$
64 = 64
$
}}$$
Yes, it is a right triangle
![]()