+0  
 
0
121
1
avatar+490 

Im very confused by this 

 Jul 7, 2022
 #1
avatar+118132 
+1

Hi Elijah    laugh

 

The parabola needs to be of the form  x^2=4ay   [The vertex is (0,0)]

a is the foacl length

 

\(x^2 =4ay=\frac{8}{5}y=4*\frac{2}{5}y \)  

 

the foacal length is 2/5 = 0.4"

 

So the bulb must be placed 0.4 inches from the vertex.

 Jul 7, 2022

12 Online Users

avatar