+501 The domain of the function $h(x) = \sqrt{25-x^2}+\sqrt{-(x-2)}$ is an interval of what width?
+1224 \(25 - x^2 \geq 0 \implies -5 \leq x \leq 5\)
\(-(x-2) \ge 0 \implies x \le 2\)
Put the two inequalities together: \(x \in [-5, 2]\). This is an interval of length 7.
