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The domain of the function $h(x) = \sqrt{25-x^2}+\sqrt{-(x-2)}$ is an interval of what width?

 Feb 21, 2021
 #1
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\(25 - x^2 \geq 0 \implies -5 \leq x \leq 5\)

 

\(-(x-2) \ge 0 \implies x \le 2\)

 

Put the two inequalities together: \(x \in [-5, 2]\). This is an interval of length 7.

 Feb 21, 2021

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