+0  
 
-1
430
1
avatar+206 

Find the domain of the function $f(x)=\sqrt{\sqrt{x^2-16}-3}$.

 Feb 21, 2021
 #1
avatar+1223 
0

\(\sqrt{x^2 - 16} \geq 3\)

 

\(x^2 - 16 \geq 9\)

 

\(x^2 \geq 25\)

 

\(\boxed{x \in (-\infty, -5) \cup (5, \infty)}\)

.
 Feb 21, 2021

3 Online Users

avatar