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Find the domain of the function $f(x)=\sqrt{\sqrt{x^2-16}-3}$.

 Feb 21, 2021
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\(\sqrt{x^2 - 16} \geq 3\)

 

\(x^2 - 16 \geq 9\)

 

\(x^2 \geq 25\)

 

\(\boxed{x \in (-\infty, -5) \cup (5, \infty)}\)

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 Feb 21, 2021

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