The domain of the equation y = 3x/(x^2 - 6x + 4) is the set of all real numbers with the exception of the values x = A and x = B. What is A + B?
The domain will include all x values except the ones that make x^2 - 6x + 4 = 0
These two values, A and B, will be the roots of this quadratic function.....by Vieta...... in the form ax^2 +bx + c.....the sum of the roots = -b /a
So we have
-(-6) / 1 = -6
A + B = -6