The domain of the equation $y = \frac{3x}{2x^2 - 6x + 4}$ is the set of all real numbers with the exception of the values $x = A$ and $x = B$. What is $A + B$?
We cannot have the denominator = 0
So....to find the values of x that make it 0, we have
2x^2 - 6x + 4 = 0 divide through by 2
x^2 -3x + 2 = 0 factor
(x - 2) ( x - 1) = 0
x -2 = 0 x -1 = 0
x = 2 x =1
A + B = 2 + 1 = 3
+193 
