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Find the domain of the function $\frac{x^4-4x^3+6x^2-4x+1}{x^2-4}$.

 Feb 17, 2021
 #1
avatar+2197 
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The denominator CANNOT be zero.

Try solving this: \(x^2-4≠0\)

 Feb 17, 2021
 #2
avatar+11438 
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Find the domain of the function $\frac{x^4-4x^3+6x^2-4x+1}{x^2-4}$.

 

Hello olivia!

 

\(x^2-4\neq0\\ x\neq\{-\sqrt{2},\sqrt{2}\} \)

\( x\in\mathbb R\ |\ x\notin\{-\sqrt{2},+\sqrt{2}\}\)

laugh  !

 Feb 17, 2021
edited by asinus  Feb 17, 2021
edited by asinus  Feb 17, 2021
edited by asinus  Feb 17, 2021

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