Find the domain of the function $\frac{x^4-4x^3+6x^2-4x+1}{x^2-4}$.
The denominator CANNOT be zero.
Try solving this: \(x^2-4≠0\)
Hello olivia!
\(x^2-4\neq0\\ x\neq\{-\sqrt{2},\sqrt{2}\} \)
\( x\in\mathbb R\ |\ x\notin\{-\sqrt{2},+\sqrt{2}\}\)
!
!
+206 
