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Find the domain of the real-valued function

f(x) = -sqrt(-10x^2 - 4x + 6)

 

Give the endpoints in your answer as common fractions, not mixed numbers or decimals.

 May 16, 2022
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Find the domain of the real-valued function

 

Hello Guest!

 

\(f(x) = -\sqrt{-10x^2 - 4x + 6}\\ (-10x^2 - 4x + 6)\geq 0\\ x^2+ \frac{2}{5}x-\frac{3}{5}\\ x=-\frac{1}{5}\pm \sqrt{\frac{1}{25}+\frac{3}{5}}\\ x=-\frac{1}{5}\pm \sqrt{\frac{16}{25}}\)

\(x\in\{-1,\frac{3}{5}\}\)

\(\color{blue}D=\{x\in \mathbb R\ |\ -1\leq x\leq \frac{3}{5}\}\)

\(\)

laugh  !

 May 16, 2022

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