What is the domain of the real-valued function f(x) = (2x - 7)/sqrt(x^2 - 7x + 6)?
\(2x-7\over\sqrt{x^2-7x+6}\)
That means the denominator has to be Greater or Equal to 0.
(x-6)(x-1) = 0, x = 1 and 6 for values of 0.
x^2 - 7x + 6 > 0
(x - 6)(x - 1)>0, double neg or double pos.
x>6 and x<1
Domain: (-inf, 1] U [6, inf)
