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What is the domain of the real-valued function f(x) = (2x - 7)/sqrt(x^2 - 7x + 6)?

 Oct 11, 2022
 #1
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\(2x-7\over\sqrt{x^2-7x+6}\)

That means the denominator has to be Greater or Equal to 0.

(x-6)(x-1) = 0, x = 1 and 6 for values of 0. 

x^2 - 7x + 6 > 0 

(x - 6)(x - 1)>0, double neg or double pos.

x>6 and x<1

Domain: (-inf, 1] U [6, inf)

 Oct 11, 2022

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