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Find the domain of the function f(x) = sqrt(sqrt(x^2 - 16) + 3).

 Mar 12, 2021
 #1
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We  must  have that

 

sqrt (x^2 - 16) + 3    ≥  0

 

All we  really  need to worry  about    is   that  x^2   -  16  ≥  0

 

This will  be  true  on  two  intervals

 

(-inf , -4  ]   U  [ 4 , inf)     = the domain

 

See the graph here  ;   https://www.desmos.com/calculator/htuz2jh2j9

 

 

cool cool cool

 Mar 12, 2021

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