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How many real numbers are not in the domain of the function

 

f(x) = 1/(x - 64) + 1/(x^2 - 64) + 1/(x^3 - 64) + 1/(x^4 - 64)

 Apr 28, 2021
 #1
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A number will not be possible if the denominator is 0, since you can't divide a number by 0. 

We have 4 denominators, x-64, x^2-64, x^3-64, x^4-64. 

Figure out the number of x where at least one of them equals to 0.

 

=^._.^=

 Apr 28, 2021

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