Domain

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Compute the domain of the real-valued function $f(x) = \sqrt{1 + \sqrt{2 - \sqrt{x}}}$ .

Guest Jun 10, 2021

ElectricPavlov · Answer 1 · 2021-06-10T09:46:34

Square root cannot be negative

so for the first part sqrt (x) the domain is x >= 0

then it is subtracted from two and squre 'rooted' again ....cannot be negative

so x must be between 0 and 4 inclusive

then it is added to 1 before taking the square root again....if the previous step was positive or zero, this will be too...

[ 0 , 4 ]