What is the domain of the real-valued function f(x) = (2x - 7)/sqrt(x^2 - 7x + 6)?
The denominator cannot = 0
So x^2 -7x +6 = (x -6) (x - 1) so x cannot be 1 , 6
Also x^2 - 7x + 6 must be ≥ 0
So
(x -1) (x -6) ≥ 0
This is true whenever x < 1 and x > 6
The domain is ( -inf , 1) U ( 6 ,inf)
