The domain of the equation y = 3x/(x^2 - 5x - 4) is the set of all real numbers with the exception of the values x = A and x = B. What is A + B?

In order for the domain to not work, the denominator.

x^{2}-5x-4=0

\(x = {5 \pm \sqrt{25+16} \over 2}\)

A = (5+√41)/2

B = (5-√41/2)

A+B = (5+√41+5-√41)/2

A+B = 5