How do i get 0 if my question looks like this? x/2+(3*2)+sqr(16)
If x=-20.
PROOF
\({x\over2}+(3*2)+{\sqrt16}=0\)
\({x\over2}+6+4=0\)
\({x\over2}+10=0\)
\({x\over2}=-10\)
\(x=-20\)
CHECK
\({-20\over2}+6+4=0\)
\(-10+10=0\)
\(0=0\)
Thx m(sqr(64))
+5265 
