The tranverse axis contains the two foci and two vertices
Thus.....this hyperbola intersects the x axis
So....the form will be
(x - h)^2 (y - k)^2
_______ - ________ = 1
a^2 b^2
(h, k) = (-3, 2)
2a = 12 2b = 8
a = 6 b = 4
So we have
(x + 3)^2 ( y - 2 )^2
________ - _________ = 1
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