Find the constant $k$ such that the quadratic $2x^2 + 3x + 8k + 3x^2 + 2x + k$ has a double root.
Find the constant $k$ such that the quadratic $2x^2 + 3x + 8k + 3x^2 + 2x + k$ has a double root.
2x2 + 3x + 8k + 3x2 + 2x + k
combine like terms, and arrange in standard form ax2 + bx + c
5x2 + 5x + 9k
an equation has a double root when its discriminant equals zero
b2 – 4ac = 0
52 – (4)(5) • 9k = 0
25 – 180k = 0
– 180k = – 25
k = 25 / 180
k = 5 / 36
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