dP/dt = 0.02P, P(0)=20.
Please show workings with all steps.
I have 0.02t^1.02/1.02=ln|P+C|, and the final solution is P=20e^0.02t. I cannot get from my solution to the final solution right?
Separating the variables and integrating, we have
∫1/P dp = ∫.02 dt
ln P = .02t + C
This says that
e^(.02t + C) = P .....or.....
(e^C)* e^(.02t) = P
And e^C is just a constant....we can just call it "C"
And we have P(0) = 20 .... so...
Ce^(.02(0)) = 20
Therefore, C = 20
And our answer is
P = 20e^(.02t)
I hope this helps.....