+912 Drag and drop a statement or reason to each box to complete the proof.
Given: parallelogram EFGH
Prove: EG¯¯¯¯¯ bisects HF¯¯¯¯¯¯ and HF¯¯¯¯¯¯ bisects EG¯¯¯¯¯ .
Statement Reason
parallelogram EFGH Given
EF¯¯¯¯¯ ≅ HG¯¯¯¯¯¯ ( )
EF¯¯¯¯¯ ∥ HG¯¯¯¯¯¯ ( )
( ) ( )
△EKF ≅△ GKH ASA Congruence Postulate
( ) CPCTC
EG¯¯¯¯¯ bisects HF¯¯¯¯¯¯ and HF¯¯¯¯¯¯ bisects EG¯¯¯¯¯ . Definition of bisector
OPTIONS: EK¯¯¯¯¯≅ GK¯¯¯¯¯
FK¯¯¯¯¯≅ HK¯¯¯¯¯ ,
