Dragonlance thank you for your help. The second part of that problem ask me to determine how long and what year the population in Ky may double assuming a steady growth rate, Can you help me with this as well? Thank you Tiffanie
+1316 OK to figure out how long it will take for the population to double take the Log(2)/Log(1.009) The 2 mean to double.
$${\frac{{log}_{10}\left({\mathtt{2}}\right)}{{log}_{10}\left({\mathtt{1.009}}\right)}} = {\mathtt{77.362\: \!409\: \!451\: \!566\: \!917\: \!5}}$$
The rate is per year so it will take 77.4 years to double the population.
+1316 Hi Tiffanie, I can help. You should look at my second post on the other one because the rate number you post might not have been the right one. I not expect you to answer because most Anons never reply.
I will work on this one now.
+1316 OK to figure out how long it will take for the population to double take the Log(2)/Log(1.009) The 2 mean to double.
$${\frac{{log}_{10}\left({\mathtt{2}}\right)}{{log}_{10}\left({\mathtt{1.009}}\right)}} = {\mathtt{77.362\: \!409\: \!451\: \!566\: \!917\: \!5}}$$
The rate is per year so it will take 77.4 years to double the population.
