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In triangle ABC, angle B = 90 degrees. Point X is on line AC such that angle BXA = 90 degrees, AX = 15, and CX = 5. What is BX?

 Apr 30, 2024
 #1
avatar+128772 
+1

A

 

       15

          X

                 5

B                   C

 

ABC  ≈  BXC

ABC  ≈  AXB

 

So

 

BXC  ≈  AXB

 

BX / CX  =  AX / BX

 

BX^2  = AX * CX

 

BX^2 =  15 * 5

 

BX^2 = 75

 

BX =  sqrt (75)  =  5sqrt (3)

 

cool cool cool

 Apr 30, 2024

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