A triangle has side lengths of $10,$ $24,$ and $26.$ Let $a$ be the area of the circumcircle. Let $b$ be the area of the incircle. Compute $a - b.$
We know that this is a right triangle
To find the circumcircle radius, we can just divide the hypotnuse of the triangle by 2, or 26/2 = 13, as the hypotnuse passes through the center of the circle.
To find the incircle radius, it is (leg1 + leg2 - hypotnuse)/2, or (10+24-26)/2 = 4
Hope this helps you :D
13^2 - 4^2pi= 169pi-16pi = 153pi :)