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There exist constants a, h, and k such that 3x^2+12x+4=a(x-h)^2+k
for all real numbers x.  Enter the ordered triple (a,h,k)

 Mar 13, 2020
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This is an exercise in completing the square: 3x^2 + 12x + 4 = 3(x + 1)^2 + 1, so (a,h,k) = (3,-1,1).  

 Mar 13, 2020

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