+0  
 
+5
510
6
avatar+1832 

How can I solve this problem  ? 

 

physics
xvxvxv  Jan 5, 2016

Best Answer 

 #5
avatar+1311 
+5

This is cool!

 

OK I get 8.93 feet in one second. What do you get XV

Dragonlance  Jan 5, 2016
 #1
avatar+8613 
0

Do you have a formula at all?

Hayley1  Jan 5, 2016
 #2
avatar+1832 
0

conservation of linear momentum
 

xvxvxv  Jan 5, 2016
 #3
avatar+8613 
+3

I don't know how to do this, I'm really sorry :(

Hayley1  Jan 5, 2016
 #4
avatar+26750 
+5

Initial momentum of the system = 0.

 

Crate acceleration along ramp = g*3/5   (component of g along ramp)

 

Velocity of crate (along ramp) at B given by  v^2 = 2*(g*3/5)*L   (L = length of ramp).

 

Horizontal component of crate velocity vcrate = -v*4/5   (with horizontal velocity positive to the right).

 

Momentum of system when crate reaches B:    mcrate*vcrate + mramp*vramp = 0

 

See if you can take it from here.

Alan  Jan 5, 2016
 #5
avatar+1311 
+5
Best Answer

This is cool!

 

OK I get 8.93 feet in one second. What do you get XV

Dragonlance  Jan 5, 2016
 #6
avatar+1832 
+5

I understood what you wrote Alan, 

but the book answer confusses me, 

 

 

 

why did he put the kinatic energy of the ramp in the equation of conservation of energy ?! 

it suppose to be for the box ! 

xvxvxv  Jan 6, 2016

14 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.