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e= (1.7*10^3J)-(3.3*10^2J)                  I got 1.4*10^-3J but i dont think it is right. 

            (1.7*10^3J)

 Aug 9, 2016
 #1
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=.8059J =8.059 x 10^-1J

 Aug 9, 2016
 #2
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e= (1.7*10^3J)-(3.3*10^2J)                  I got 1.4*10^-3J but i dont think it is right. 

            (1.7*10^3J)

 

\(\begin{array}{|rcll|} \hline e &=& \dfrac{(1.7*10^3J)-(3.3*10^2J)}{(1.7*10^3J)} \\\\ e &=& \dfrac{1.7*10^3J}{1.7*10^3J} -\dfrac{3.3*10^2J}{1.7*10^3J} \\\\ e &=& 1 -\dfrac{3.3*10^2{\color{red}\not} J }{1.7*10^3{\color{red}\not} J } \\\\ e &=& 1 -\dfrac{3.3*10^2 }{1.7*10^3 } \\\\ e &=& 1 -\dfrac{3.3*10^{2-3} }{1.7} \\\\ e &=& 1 -\dfrac{3.3*10^{-1} }{1.7} \\\\ e &=& 1 -\dfrac{0.33}{1.7} \\\\ e &=& 0.80588235294 \\ e &=& 8.0588235294 *10^{-1}\\ \hline \end{array}\)

 

laugh

 Aug 10, 2016

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