e^(-2j)

Looks good Melody.

The question is already in simplest form, could you clarify what you mean better?

maybe, if j = sqrt(-1)  then

$$\\e^{-2j}\\\\ =cos(-2)+isin(-2)\qquad $in radians$\\\\ \approx \;-0.4161-0.9093j$$

Could a mathematician please check this.   

Thanks Bertie :)