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e^(-2j) solve it.

Guest Feb 22, 2015

Best Answer 

 #3
avatar+889 
+5

Looks good Melody.

Bertie  Feb 23, 2015
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4+0 Answers

 #1
avatar+69 
+5

The question is already in simplest form, could you clarify what you mean better?

silver27  Feb 22, 2015
 #2
avatar+92254 
+5

maybe, if j = sqrt(-1)  then

 

$$\\e^{-2j}\\\\
=cos(-2)+isin(-2)\qquad $in radians$\\\\
\approx \;-0.4161-0.9093j$$

 

Could a mathematician please check this.   

Melody  Feb 23, 2015
 #3
avatar+889 
+5
Best Answer

Looks good Melody.

Bertie  Feb 23, 2015
 #4
avatar+92254 
0

Thanks Bertie :)

Melody  Feb 24, 2015

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