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e^(2sinx)=1    

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 Jun 21, 2017
edited by Guest  Jun 21, 2017
edited by Guest  Jun 21, 2017
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For e^anything to be 1 we must have anything=0. Thus here we must have sinx =0.

 

This means x can be 0 or any integer multiple of pi.

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 Jun 21, 2017
edited by Alan  Jun 21, 2017

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